Where is size t

In an implementation where unsigned int is 32 bits, the biggest number it can represent is Some processors, such as the IP16L32, can copy objects larger than bytes. So, you ask, why not use an unsigned long int? It exacts a performance toll on some platforms. Standard C requires that a long occupy at least 32 bits. Collectives on Stack Overflow. Learn more. Ask Question. Asked 11 years, 7 months ago. Active 2 months ago. Viewed k times. Improve this question.

Peter Mortensen 29k 21 21 gold badges 97 97 silver badges bronze badges. Vijay Vijay Nate That is incorrect. As stated in the book, using an index int i may not be enough to address a huge array. Add a comment. Active Oldest Votes. Improve this answer.

Community Bot 1 1 1 silver badge. Draemon That comment reflects a fundamental confusion. Still, the quoted text doesn't say "sizes of in-memory objects", and "offset" is hardly a good name for a size type regardless of where it happens to be stored.

Draemon Good point. This answer quotes Wikipedia, which in this case doesn't have the best explanation, in my opinion. Section 6. Since you cannot apply sizeof to a disk file mostly because C doesn't even define how disks and files work , there is no room for confusion.

In other words, blame Wikipedia and this answer for quoting Wikipedia and not the actual C standard. Draemon - I would also agree with the "fundamental confusion" assessment. Read the C standard, which has none of those OOP objects, but yet has objects, and find out. The answer may surprise you! Show 10 more comments. Gaurang Tandon 5, 10 10 gold badges 40 40 silver badges 76 76 bronze badges.

Alok Singhal Alok Singhal JasonOster, two's complement is not a requirement in the C standard. If the value of s2 - s1 overflows an int , the behavior is undefined. Show 7 more comments. Arjun Sreedharan Arjun Sreedharan 9, 1 1 gold badge 21 21 silver badges 33 33 bronze badges.

Case in point: bit Windows. Show 1 more comment. If you are the empirical type , echo gcc -E -xc -include 'stddef. Thanks for sharing this awesome command Ciro, it helped me a lot!

The matter itself is not confusing. It is the confusing mind that tries to ask many questions, and give many answers. I am surprised that this answer and the one by Arjun Sreedharan still do not stop people from asking and answering. DeanP: Perhaps not, though there would then be a question of what argument type should be used for things like malloc.

Personally, I would have liked to have seen versions which take arguments of type int , long , and long long , with some implementations promoting shorter types and others implementing e. In all other cases, a call to ranges::size is ill-formed, which can result in substitution failure when ranges :: size t appears in the immediate context of a template instantiation. Expression e is expression-equivalent to expression f , if e and f have the same effects, either are both potentially-throwing or are both not potentially-throwing i.

The name ranges::size denotes a customization point object , which is a const function object of a literal semiregular class type. Thus, ranges::size can be copied freely and its copies can be used interchangeably. Given a set of types Args Whenever ranges :: size e is valid for an expression e , the return type is integer-like. All implementations directly return the prvalue instead.